android端集成im即时通讯，登录注册失败，208失败码code，有没有大佬帮忙解决一下

package com.example.myapplication8;

import androidx.appcompat.app.AppCompatActivity;

import android.os.Bundle;
import android.util.Log;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.Toast;

import com.hyphenate.chat.EMClient;
import com.hyphenate.exceptions.HyphenateException;

public class RegistActivity extends AppCompatActivity implements View.OnClickListener {

    private EditText register_username;
    private EditText register_password;
    private EditText register_confirm_password;
    private Button register_submit;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_regist);
        initView();
    }

    private void initView() {
        register_username = findViewById(R.id.register_username);
        register_password = findViewById(R.id.register_password);
        register_confirm_password = findViewById(R.id.register_confirm_password);
        register_submit = findViewById(R.id.register_submit);
        register_submit.setOnClickListener(this);
    }

    @Override
    public void onClick(View v) {
        switch (v.getId()){
            case R.id.register_submit:
                StartRegister();
                break;
            default:
                break;
        }
    }

    //点击注册
    private void StartRegister() {
        String string_username = register_username.getText().toString().trim();
        String string_password = register_password.getText().toString().trim();
        String string_confirm_password = register_confirm_password.getText().toString().trim();

        Log.d("TAG", "StartRegister: "+ValidUtil.isValidUserName(string_username)+
                ValidUtil.isValidPassWord(string_password));
        if (ValidUtil.isValidUserName(string_username)){
            if (ValidUtil.isValidPassWord(string_password)){
                if (ValidUtil.isValidPassWord(string_confirm_password)&&string_password.equals(string_confirm_password)){
                    // 注册失败会抛出 HyphenateException。
                    // 同步方法，会阻塞当前线程。
                    new Thread(new Runnable() {
                        @Override
                        public void run() {
                            try {
                                EMClient.getInstance().createAccount(string_username, string_password);
                                runOnUiThread(new Runnable() {
                                    @Override
                                    public void run() {
                                        Toast.makeText(RegistActivity.this, "注册成功！", Toast.LENGTH_SHORT).show();
                                        finish();

                                    }
                                });
                            } catch (HyphenateException e) {
                                e.printStackTrace();
                                runOnUiThread(new Runnable() {
                                    @Override
                                    public void run() {
                                        Toast.makeText(RegistActivity.this, "注册失败！"+e.getErrorCode(), Toast.LENGTH_SHORT).show();
                                    }
                                });
                            }
                        }
                    }).start();
                }
            }else {
                Toast.makeText(this, ValidUtil.TOAST_ERROR_PASSWORD, Toast.LENGTH_SHORT).show();
            }
        }else {
            Toast.makeText(this, ValidUtil.Toast_ERROR_USERNAME, Toast.LENGTH_SHORT).show();
        }
    }



}

好像是创建应用时选择开放注册就可以解决